CODEBREAKER X11

[gandalf the untidy]

How are you a finding the next in the series, 1 point per answer

1. o,t,t,f,f,s,s,?, E for 8 in the sequence one,two,three,four etc

2. 7, 14, 17, 21, 27, 28, 35, 37, ?, ?, consecutive nos containing or divisible by 7

3. 4, 6, 12, 18, 30, 42, 60, 72, 102, 108, ?, ?, (toughie worth 5 points) i thought this was quite difficult but a very quick solution from tommo, numbers that have a prime number on each side e.g 12 is bounded by the prime numbers 11 & 13 so the next 2 in the sequence are 130 and 158

4. 77, 49, 36, 18 ? 7x7=49, 4x9=36, 3x6=18 so 1x8=8

5. 2 9 3 1 8 4 3 6 5 7 ? two sequences here 2,3,4,5 etc with altenate 2x9,2x18,2x36=72
therefore the next no is 2

6. 2, 3, 3, 5, 10, 13, 39, 43, 172, 177, ? the sequence goes +1,X1,+2,X2,+3,X3 etc so 177x5 is 885

7. 2, 4, 6, 30, 32, 34, 36, 40, 42, 44, ? the next number to contain no "E"s is 46

8.Rectify the following equality 101 - 102 = 1 by moving just one digit. change the "2" to a squared sign so 101-10squared = 1

9. 1 3 7 12 18 26 35 45 56,69,83 the numbers in the series increase by the consecutive numbers not used in the series which are 2,4,5,6,8,9,10,11,13 & 14

10.E,O,E,R,E,X,N,T,E,? N (onE, twO, threE, fouR, fivE, siX, seveN, eighT, ninE)

1. e   (1,2,3,4,5,6,7,8)
2. 42, 47.  (Numbers either contain 7 or are divisible by 7.)
3. 138, 150

[daveuk1]

5.  2   2 9 3 18 4 36  5 72

[gandalf the untidy]

Apr 12, 2013 18:55:50 GMT tommo III said:

1. e   (1,2,3,4,5,6,7,8)
2. 42, 47.  (Numbers either contain 7 or are divisible by 7.)
3. 138, 150

all correct for 7 quizmeister points

[gandalf the untidy]

Apr 12, 2013 19:33:20 GMT daveuk1 said:

5.  2   2 9 3 18 4 36  5 72

Correct for 1 point daveuk1

8. Levitate the 2 !  Then 101 minus 10 squared equals one. :D

[gandalf the untidy]

Apr 12, 2013 21:27:50 GMT tommo III said:

8. Levitate the 2 !  Then 101 minus 10 squared equals one. :D

looks like a plan....1 point

[daveuk1]

4 8 ..... 77 (7x7)= 49 (4x9)= 36 (3x6)= 18 (1x8) = 8

6 885 ..... 177 x5

7 46 The next number without a letter E

[gandalf the untidy]

Apr 14, 2013 17:13:38 GMT daveuk1 said:

4   8 ..... 77 (7x7)= 49 (4x9)= 36  (3x6)=  18  (1x8) = 8

6   885 ..... 177 x5

7   46 The next number without a letter E

guess you like my little testers daveuk1 3 more points, just 9 and 10 outstanding

[Dunplaying]

9. 56, 69, 83... (The R sequence of the Hofstadter figure-figure sequence where each number appears either in the R sequence or the S (difference) sequence) The difference increases by 1 unless it has already appeared in the R sequence.
10. N (onE, twO, threE, fouR, fivE, siX, seveN, eighT, ninE)

[specialone]

9. 57 70 84. The numbers increase by 2 and then 1 three times then back to 2.

[gandalf the untidy]

Apr 14, 2013 22:32:49 GMT Dunplaying said:

9. 56, 69, 83... (The R sequence of the Hofstadter figure-figure sequence where each number appears either in the R sequence or the S (difference) sequence) The difference increases by 1 unless it has already appeared in the R sequence.
10. N (onE, twO, threE, fouR, fivE, siX, seveN, eighT, ninE)

hi dun,

9. Your answer is correct, a good answer for those people who slightly understand it, in laymans terms....the numbers in the series increase by the consecutive numbers not used in the series which are 2,4,5,6,8,9,10,11 & 13

10. correct

2 points

[gandalf the untidy]

Codebreaker X11 now complete

final points

Tommo 8 pts
Daveuk1 4 pts
Dunplaying 2ts

Codebreaker X remains outstanding code 3 and code 4 have the same solution matrix so only worth 5 points each but  with the greater number of characters to work on it should be easiler to resolve with a added bonus of finding a clue to solve code 1 which i must say is brilliantly simple....when you know the answer ::)

good luck codebreakers

regs cs